The answer is 12. Thanks (;
V = 1/3* h * r^3 pi
V ' = 1/3* h/3* (2r)^3 pi = h/9 * 8r^3 * pi
V ' / V = (h/9 * 8r^3 * pi) ÷ ( 1/3* h * r^3 pi ) = (8 * 3)/ 9 = 8 /3
Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
80x3/8=10 common factor. 10x5. And 10x3
50/30
30 boys
50 girls
