The time that the ball is in the air if the player lets the ball drop is 2.145 sec
What is a quadratic equation?
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax²+ bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
-16t²+32t+5
by comparing this equation to the standard form of the quadratic equation we get
a=-16 b=32 c=5
the time (t) needed for the ball to reach its maximum height using the axis of symmetry formula (x = -b/2a) for a parabola:
the time at which the ball reaches the maximum height using the axis of symmetry formula is (x=-b/2a)
t = -32/2×-16
t=1sec
by putting h(t) to zero and determining the time (t) when the ball hits the ground:
-16t²+32t+5=0
-16(t²+2t+5/16)=0
t²-2t-5/16=0
(t)²-2×1×t+(1)²-5/16=1
(t-1)²=21/16
t-1=√21/√16
t=1+4.58/4
t=1+1.145
t=2.245sec
Learn more about quadratic equations here:
brainly.com/question/1214333
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Answer:
F) 6/5
Step-by-step explanation:
6 divided by 5 = 6/5
Answer:
Concept: Physics Qualitative Analysis.
- Scalar values are constant and compared to vector values they do not have a direction or magnitude or a gradient representation.
- Lets get started by setting up the equation
- They want us to find 3U-2V
- Given U= <6,6> V=<6,-6>
- Now we plug in and solve!
- 3<6,6>- 2<6,-6>
- <18,18>-<12,-12>
- Subtract
- <18-12,18-(-12)>
- Hence that gives us a result of <6,30>
- Now with the skills you gained solve the rest!!!
