Answer:
The first 5 terms of the sequence is 2,7,15,26,40.
Step-by-step explanation:
Given : Consider the sequence defined recursively by 
To find : Write out the first 5 terms of this sequence ?
Solution :
and
The first five terms in the sequence is at n=1,2,3,4,5
For n=1,
For n=2,
For n=3,
For n=4,
For n=5,
The first 5 terms of the sequence is 2,7,15,26,40.
Hi GlaxyCraft4991,
Solution:
−12x − 0.4 > 0.2 (36.5x + 80) − 55
−12x − 0.4 > 7.3x − 39
−12x − 0.4 − 7.3x > 7.3x − 39 − 7.3x
−19.3x − 0.4 > −39
−19.3x − 0.4 + 0.4 > −39 + 0.4
−19.3x > −38.6
−19.3x/19.3 > −38.6/19.3
x < 2
Correct Answer:
x < 2
Answer: y= x-2
Step-by-step explanation:
Perpendicularity entails the slope of line a is -1 divided by the slope of line b
m1= (-1/m2)
From y=Mx +c
We compare with x-4y=7
y=(1/4)x-7/4
Meaning m2= 1/4
m1= -1/(1/4)= -1*4= -4
((y-y1)/(x-x1))= ((y2-y1)/(x2-x1))=m1
x1= 2, y1= -4
((y-(-4))/(x-2))= -4
((y+4)/(x-2))= -4
Cross multiply
y+4= -4(x-2)
y= x-2
Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)
ANSWER:
a = 11
b = 2
Explaination:
We have two equations:
a = 5b + 1 .....................(1)
a = 3b + 5.....................(2)
Here we use substitution method in order to solve the set of equations.
put a=3b+1 to equation (1)
3b + 5 = 5b + 1
Solve for b
5 = 5b -3b + 1
5-1 =2b
4 = 2b
b = 2
Now put the value of b = 2 into the equation (1) or (2)
a = 5b + 1
a = 5(2) + 1
a = 10 + 1
a = 11
