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____ [38]
3 years ago
6

What is 4x + 2 = 7x + 9

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0

4X=7X+7

-3X=7

X= -3/7

                   

Over [174]3 years ago
8 0

Hi!

This question is about math.

4x + 2 = 7x + 9

<em>First subtract 2 from both sides.</em>

4x+2-2=7x+9-2

<em>Then simplify.</em>

4x-7x=7x+7-7x

<em>Simplify again.</em>

-3x=7

<em>Divide both sides by -3</em>

\frac{-3x}{-3}=\frac{7}{-3}

<em>Simplify </em>

x=-\frac{7}{3}

Hope this helps you. Thank you for posting your question at here on Brainly.

-Charlie

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There are six possible outcomes and one favourable event (2 is the only one even prime number), so the probability is \dfrac{1}{6}.
4 0
3 years ago
Solve the equation. <br><br><br> 3p/8-13=-25
dusya [7]

3p/8 - 13 = -25

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6 0
3 years ago
Read 2 more answers
The sum of three numbers is 103. The second number is 5 less than the first. The third number is 4 times the first. What are the
madreJ [45]

Answer:

The numbers are 18, 13, and 72.

Step-by-step explanation:

Let the three numbers be represented by <em>a, b</em>, and <em>c</em>.

The sum of the three is 103. Thus, we can write that:

a+b+c=103

The second number is five less than the first. So:

b=a-5

And the third number is four times the first. So:

c=4a

Substitute:

a+(a-5)+(4a)=103

Solve for <em>a</em>. Combine like terms:

6a-5=103

Add five to both sides:

6a=108

And divide both sides by six. Therefore:

a=18

So, the first number is 18.

Since the second number is five less than the first, the second number is 13.

And since the third number is four times the first, the third number is 72.

6 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
In-s [12.5K]

Answer:

8

Step-by-step explanation:

f^-1(x) =dy/dx

dy/dx(8x+9)=8

8 0
3 years ago
Find x1 and x2.
stepladder [879]

Answer:

x_1 = 7\\x_2 = 6

Step-by-step explanation:

To find x₁ and x₂ :

\left[\begin{array}{ccc}-4&1\\5&4\\\end{array}\right] \times \left[\begin{array}{ccc}x_1\\x_2\\\end{array}\right] + \left[\begin{array}{ccc}11\\-19\\\end{array}\right] = \left[\begin{array}{ccc}-11\\40\\\end{array}\right]

Step 1

Multiply first 2 x 2 matrix with 2 x 1 vector, we get

\left[\begin{array}{ccc}-4x_1&+  x_2\\5x_1&+  4x_2\\\end{array}\right] + \left[\begin{array}{ccc}11\\-19\\\end{array}\right] = \left[\begin{array}{ccc}-11\\40\end{array}\right]

Step 2

Add the 2 x 1 matrices on LHS, we get

\left[\begin{array}{ccc}-4x_1&+x_2&+11\\5x_1&+4x_2&-19\\\end{array}\right] = \left[\begin{array}{ccc}-11\\40\end{array}\right]

Step 3,

we get

-4x_1 + x_2 + 11 = -11

and

5x_1 + 4x_2-19=40

Step 4,

Simplify, we get

-4x_1+x_2=-22----(1)\\ 5x_1+4x_2=59----(2)

Step 5,

multiply eqn(1) by 4

we get

16x_1+4x_2=-88

Step 6,

eqn (2) - eqn(3)

we get

21x_1 = 147\\x_1 =\frac{147}{21} \\x_1= 7

substituting in eqn (1), we get

(-4 \times 7) + x_2 = -22

so, we get

x_2 = 6

Therefore

x_1 = 7\\x_2 = 6

5 0
3 years ago
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