Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
Answer:
y=-5x+19
Step-by-step explanation:
yeah -ya...... right?
Answer:
5x-2
Step-by-step explanation:
15x^2-x-2
15x^2+5x-6x-2
factorize
5x(3x+1)-2(3x+1)
Sol: (3x+1)*(5x-2)
The answer is 3
hope this helps :)
Answer:
2x^2 - 3x - 1
Step-by-step explanation: