Answer:
7
Step-by-step explanation:
8(7)=56
The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
Answer:
8.75cm²
Step-by-step explanation:
First we need to find the angle subtended by the arc
L = theta/360 * 2pir
3.5 = theta/360 * 2*3.14(5)
3.5 = theta/360 * 31.4
theta/360 = 3.5/31.4
theta/360 = 0.11146
theta = 0.11146 * 360
theta = 40.13 degrees
Area of the sector = theta/360 * pir^2
Area of the sector = 40.13/360 * 3.14*25
Area of the sector = 40.13/360 * 78.5
Area of the sector = 8.75cm
Hence the area of the sector is 8.75cm²
Answer:
-4 or -9
Step-by-step explanation:
-a^2-13a-36=0
(-a-4)(a+9)=0
-a-4=0
a+9=0
a= -4, -9
Answer:
706.85775
Step-by-step explanation:
First you find the volume of the tank
13*3.14159=40.84067
40.84067*75=3063.05025
Then find the volume of both the tank and sleeve
13+3=16
16*3.14159=50.26544
50.26544*75=3769.908
Subtract the original volume with the combined volume
3769.908-3063.05025=706.85775
