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jeyben [28]
3 years ago
8

The air pressure inside Jason's bike tires decreases by about 6% each week. The original pressure was 45 pounds per square inch

(psi). What is the tire pressure after 6 weeks?
Mathematics
1 answer:
Fudgin [204]3 years ago
8 0
Lets do this week by week 
beginning pressure 45 pounds 
end of week 1 
45 *.06 = 2.7
45 - 2.7 = 42.3
end of week 2 
42.3 * .06 = 2.538
42.3 - 2.538 = 39.762
end of week 3 
39.762 *.06 = 2.38
39.762 -  2.38 = 37.37
end of week 4
37.37* .06 = 2.2425
37.37628 - 2.2425= 35.12
end of week 5
35.12 * .06 = 2.107
35.12 - 2.107 = 33.012
end of week 6 
33.012* .06 = 1.98
33.012 - 1.98 =31.03

Here is the fast way to get to this answer. 
do 1-.06 = .94

then do 
45(.94)(.94)(.94)(.94)(.94)(.94)  = 31.04 


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Step by step:

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Find the coordinates of point Q that lies along the directed line segment from R(-2, 4) to S(18, -6) and partitions the segment
Alexandra [31]

Answer:

The coordinates of the point Q is (4, 1)

Step-by-step explanation:

The given parameters are;

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The ratio in which the point Q partitions the directed line segment = 3:7

Therefore, the proportions of the R to Q = 3/(3 + 7) = 3/10 the length of RS

Which gives;

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The coordinates of the point Q = (4, 1)

We check the length from R to S is given by the relation for length as follows

l =\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

R(-2, 4) = (x₁, y₁)

S(18, -6) = (x₂, y₂)

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length from R to Q = 6.7086

We check RQ/RS = 6.7082/22.36 = 0.3

Also QS/RS = (22.36 - 6.7082)/22.36 = 0.6999≈ 0.7

The coordinates of the point Q = (4, 1).

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