For these types of problems, You must look at the coefficients and variables separately and find the GCF for each. Then, combine the two
First, take 12 and 9
Factors of both
9- 1, 3, 9
12- 1, 2, 3, 4, 6, 12
So the gcf of 12 and 9 is 3
Now do the variables a and a^2
a^2 is just a twice
The GCF is a
Now combine a and 3
Answer: GCF is 3a
Answer:
B) 6 tan(35°)
Step-by-step explanation:
from the right angle tan° = opposite / adjacent
therefore tan (35°) = (x) / 6
by multiplying 6 to both sides
tan (35°) * 6 = (x) / 6 * 6
therefore (x) = 6 tan (35°)
<span>2x^3 + 10x^2 + 4x + 20
= 2(x^3 + 5x^2 + 2x + 10)
= 2[x^2(x + 5) + 2(x + 5)]
= 2[(x+5)</span>(x^2 + 2)<span>]
answer
</span>2[(x + 5)(x^2 + 2)]
Answer:
The answer is A.
Step-by-step explanation:
15-(m+p)=
15-(3+10)=
15-13=
2
Hope this helps <3
Answer:
Because is cannot be evenly divided by 2.