6,000,000 + 7,000+ 200 is your expanded form
hope this helps
Answer: rounded to the tens is 10 the tens place is the one in 12.81 or like the one in 13.81
Step-by-step explanation:
Answer:
it changed 21 Fahrenheit
Step-by-step explanation:
-14.8 - 6.2 = -21
and minus + minus = +
so, -14.8 + 21 = 6.2
i think so that is the right answer
An alternating series

converges if

is monotonic and

as

. Here

.
Let

. Then

, which is positive for all

, so

is monotonically increasing for

. This would mean

must be a monotonically decreasing sequence over the same interval, and so must

.
Because

is monotonically increasing, but will still always be positive, it follows that

as

.
So,

converges.
Answer:
Midpoint is (0, -4)
Step-by-step explanation:
x-coordinate of midpoint = (-7 + 7)/2 = 0/2 = 0
y-coordinate of midpoint = (3 - 11)/2 = -8/2 = -4
Midpoint is (0, -4)