All categories

3 years ago

Really need help with this plsss answer

Mathematics

1 answer:

Nutka1998 [239]3 years ago

3 0

Point slope form is:

y - $y_{1}$ = m(x - $x_{1}$ )

With $y_{1}$ and $x_{1}$ being the coordinate points, and m being the slope.

So the coordinate points are (4, -5), and the slope is -6 in this case.

So just substitute everything in, to get:

y - ( -5) = -6(x - 4)

Or

y + 5 = -6 (x - 4)

You might be interested in

Help Please I will Give Brainliest if Correct!!

KengaRu [80]

Answer:

1/25 k^2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Imani won 50 super bouncy balls playing

pantera1 [17]

Answer:

Step-by-step explanation:

50-2= 48

48 divide by 2 is 16

8 0

3 years ago

Mitch has 50 pieces of licorice. He shares them equally with his sister.

leonid [27]

50/2=L is the a expression

7 0

4 years ago

Read 2 more answers

How do I do this ???

Triss [41]

Answer:

He can cut 6 sections this length.

Step-by-step explanation:

he has

7(12) = 84 inches of rope.

84-34.5 = 49.5

49.5/8.25 = 6

4 0

3 years ago

Read 2 more answers

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago