Ask question

Ask question

All categories

3 years ago

8

Which expression is equivalent to one over three p + 15? (4 points) one over three (p + 45) one over three (p + 5) 3(p + 45) 3(p

+ 5)

1 answer:

Fiesta28 [93]3 years ago

3 0

Answer:

Which expression is equivalent to one over three p + 15? (4 points)

one over three (p + 45)

one over three (p + 5)

<u>3(p + 45) </u>

3(p + 5)

Step-by-step explanation:

You might be interested in

Please help! Will give brainliest to correct answer

saveliy_v [14]

Answer:

Correct option is (C).

Step-by-step explanation:

Because in figure,

°.°point B is fixed at plane.

.°.Center is B.

& °.° Image is enlargement.

.°. scale factor will be greater than 1

Now,

scale factor = A'B'/AB

= 24/6

= 3

So correct option is (C).

#$# HOPE YOU UNDERSTAND #$#

#$¥ THANK YOU ¥$#

❤ ☺ ☺ ☺ ☺ ☺ ☺ ❤

5 0

3 years ago

Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6

musickatia [10]

Answer:

$(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Step-by-step explanation:

In order to find the values of $(x+y)^5$ and $(x+y)^6$ , you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

$(x+y)^5$ = $\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$ = $\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$ = $x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$ .

$(x+y)^6$ = $\sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i$ = $\frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6$ = $x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$ .

5 0

3 years ago

HURRY PLEASE <br><br> What is the solution of the system 4x+3y=6 2x+2y=5

jolli1 [7]

The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I

The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II

Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4

Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2

From the above calculations:
x = -3/2
y = 4

7 0

4 years ago

Read 2 more answers

1.2.6 1-118 Find each sum.<br><br> A. 3/5 + 1/3<br><br> B. 5/7 + 1/2<br><br> C. 1/6 + 2/8

Blababa [14]

A.) 14/15 B.) 17/14 C.) 5/12

8 0

3 years ago

Find the state income tax deducted: gross pay of $978, state income tax 5%

Ostrovityanka [42]

978 x .05 = 48.9 should be the tax.

3 0

3 years ago

Read 2 more answers