Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
Waxing crescent
First quarter
Waxing gibbous
Full moon
Waning crescent
Answer: (B) Prothallus
Explanation: Prothallus is the gametophyte stage in the life of <u>a fern or other pteridophyte</u>.
Answer:
Commensalism
Explanation:
Commensalism is a relationship between species in which one benefits and the other is unaffected. Humans are host to a variety of commensal bacteria in their bodies that do not harm them but rely on them for survival
Answer:
The increased activity prior to the saccade reflects a shift in attention to the stimulus inside that neuron's receptive field.
Explanation:
They observed that the neurological basis of attention, first made in the superior colliculus has been extended to a number of areas in both the dorsal and ventral streams.
