Answer:
D. 28.54
Step-by-step explanation:
To find the area of the shaded region, find the area of the circle and divide it in 4. This will the area of the portion with the triangle.
Now, find the area of the triangle and subtract the two. The resulting value will be the area of the shaded region.
Circle:

Divide by 4 for the area of the section with the triangle.
314/4 = 78.5
Triangle:

Subtract the two, 78.5 - 50 = 28.5.
For
ax^2+bx+c=
and a=1
b/2 squared=c makes a perfect square
b=16
16/2=8
8^2=64
the value of c should be 64
factored form
(x+8)^2
Answer:
<h2>
<em>x</em><em>=</em><em>3</em></h2>
<em>Sol</em><em>ution</em><em>,</em>
<em>Theorem</em><em>:</em>
<em>The</em><em> </em><em>angle</em><em> </em><em>bisector</em><em> </em><em>theorem</em><em> </em><em>states </em><em>that</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>ray </em><em>bisects</em><em> </em><em>an</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>triangle,</em><em>then</em><em> </em><em>it</em><em> </em><em>divides</em><em> </em><em>the</em><em> </em><em>oppos</em><em>ite</em><em> </em><em>side</em><em> </em><em>into</em><em> </em><em>two </em><em>segments</em><em> </em><em>that</em><em> </em><em>are</em><em> </em><em>proportional</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>two</em><em> </em><em>sides</em><em>.</em>
<em>By</em><em> </em><em>the</em><em> </em><em>theorem</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Answer: Choice D
(a-e)/f
=======================================
Explanation:
Points D and B are at locations (e,f) and (a,0) respectively.
Find the slope of line DB to get
m = (y2-y1)/(x2-x1)
m = (0-f)/(a-e)
m = -f/(a-e)
This is the slope of line DB. We want the perpendicular slope to this line. So we'll flip the fraction to get -(a-e)/f and then flip the sign from negative to positive. That leads to the final answer (a-e)/f.
Another example would be an original slope of -2/5 has a perpendicular slope of 5/2. Notice how the two slopes -2/5 and 5/2 multiply to -1. This is true of any pair of perpendicular lines where neither line is vertical.