To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
Answer:
The average is -49.
Step-by-step explanation:
You add all numbers and then divide by the numbers that your adding:
8+-67+-99+-91+-59+-81+46= -252
-252/7= -49
Answer:
110 students in the class
Step-by-step explanation: If this is helpful and correct please mark as brainliest!
Answer
Find out the m∠6 .
To prove
As given
a∥e , m∥n , and m∠2 = 112°.
As m∥n
a is the transversal (A line that cuts across two or more (usually parallel) lines is called transverasl.)
Thus
∠ 2 = ∠3 ( Corresponding angle property )
∠3 = 112°
Also
a∥e and m is transversal .
∠ 3 = ∠6 = 112 ° ( Corresponding angle property )
Therefore
∠6 = 112°