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Artemon [7]
3 years ago
7

Find the unknown length in the right triangle. If necessary, approximate the

Mathematics
1 answer:
Masja [62]3 years ago
4 0
20^2 - 16^2 = 144
[square root] 144= 12m

12m
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Solve each equation x-6=8
jok3333 [9.3K]
Equation is
x-6=8
x=8+6
x=14
X equal to 14
8 0
3 years ago
Two of your friends go bowling. One friend rents a pair of bowling shoes for $3 and bowls 3 games. The other friend brings his o
Nesterboy [21]

Answer: The cost of each game is $2.50

Step-by-step explanation:

Let's find the equations for each friend:

Friend 1:

Pays $3 for the shoes, and plays 3 games, then if X is the cost of each game, Friend 1 pays a total of:

$3 + 3*X

Friend 2:

This friend buys a soda for $0.50, and he plays 4 games, remember that the cost of each game was X. then this friend pays:

$0.50 + 4*X

And we know that both friends pay the exact same amount, then we can write:

$3 + 3*X = $0.50 + 4*X

And solve this for X.

We need to isolate X, then we can move all the terms with X to the right, and all the terms without X to the left:

$3 - $0.50 = 4*X - 3*X

$2.50 = (4 - 3)*X = X

This means the cost of each game is $2.50

4 0
3 years ago
What is the answer to 6(c+5)
Anna [14]

Answer:

6c+30

Step-by-step explanation:

Distribute it!

3 0
3 years ago
Write the exponential function that passes through the points (3, 10) and (5, 40)
tigry1 [53]

Answer:

  y = (5/4)2^x

Step-by-step explanation:

The function value increases by a factor of 40/10 = 4 when x increases by 2. The function can be written as ...

  y = (reference value)·(growth factor)^((x -reference)/(change in x for growth factor))

  y = 10·4^((x-3)/2) . . . . . . using point (3, 10) as a reference

This can be simplified to ...

  y = 10·2^(x -3) = 10/8·2^x

  y = (5/4)2^x

6 0
3 years ago
The third term of an arithmetic sequence is 14 and the 9th term is -1. Find the first four terms of the sequence.​
Liula [17]

Answer:

The first four terms of the sequence are :  19, 16.5 , 14 , 11.5

Step-by-step explanation:

In the given sequence:

a(3) =  14, a(9)  = -1

The general term of a sequence in Arithmetic Progression is:

a(n) = a + (n-1)d

a(3) = a + (3 -1) d = a + 2 d

and a(9) = a + (9- 1 ) d = a  + 8 d

⇒   a + 2 d =  14      .........  (1)

and a + 8 d  = -1    ...........  (2)

Now, solving the given system of equation, we get:

From (1), a  = 14 - 2 d

Put in (2), we get:

a + 8 d  = -1                ⇒   14 - 2 d + 8d = -1

⇒  14 +   6d   = -1  

or,  6d = -1 -14 = -15

⇒  d = -15/6 = -2.5

or, d  = -2.5

Then a  = 14 - 2 d = 14 - 2(-2.5)  =14 + 5  = 19, or a  = 19

Now, first four terms of the sequence is:

a = 19

a(2) = a + 4 = 19 - 2.5 = 16.5

a(3) = a + 2d = 19 + 2(-2.5) = 19 - 5 = 14

a(4) = a  + 3d = 19 + 3(-2.5)  = 19  - 7.5  = 11.5

Hence, the first four terms of the sequence are :  19, 16.5 , 14 , 11.5

4 0
3 years ago
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