Segment cd is the perpendicular bisector of ab at e, which pair of segments does not have to be congruent
1 answer:
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<h2>Answer</h2>
2. The Graph Contains The Point (5, 12)
<h2>Explanation</h2>Remember that in a linear function of the form ,
is the slope/rate of change of the line and
is the y-intercept.
From our equation we can infer that , so the y-intercept of our graph is 12 units above the origin on the point (0, 12). Therefore, choice 2 correctly describe the graph of y = 5x + 12
We can also infer that , so the slope of our line is 5, which is constant, so our line has a constant rate of change. Also, since every integer can be written as a fraction with denominator 1, we can write our slope as
. Therefore, choices 1 and 2 correctly describe the graph of y = 5x + 12.
Now, remember that any point on the plane has coordinates , so, to check if a point is on a line, we just need to replace the
and
values in the line equation and check if the equation holds. Our point is (5, 12), so x = 5 and y = 12. Lets replace the values in our line:
Since the equation equation doesn't hold (12 is not equal 37), we can conclude that the graph doesn't contain the point (5, 12). Therefore, choice 2 does NOT correctly describe the graph y = 5x +12.