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stellarik [79]
3 years ago
13

Verify the identity

e="csc^{2}x-csc^{2}xcos^{2}x=1" alt="csc^{2}x-csc^{2}xcos^{2}x=1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Degger [83]3 years ago
3 0

Answer:

The answer to your question is below

Step-by-step explanation:

                               csc²x - csc²x cos²x = 1

Process

1.- Convert the second term to sines

                             csc²x - cos²x/sin²x = 1

2.- Convert cos²x/sin²x to cot²x

                             csc²x - cot²x = 1

3.- Solve for csc²x

                             csc²x = 1 + cot²x

We have verified it, because there is a Pythagorean identity which sets that

                              csc²x = 1 + cot²x

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79 inches

Step-by-step explanation:

1 foot equals 12 inches

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72+7=79

79 inches

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A university is building a new student center that is two- thirds the distance from the arts center to the residential complex.
Natasha2012 [34]

Answer:

C = (\frac{21}{5},\frac{33}{5})

Step-by-step explanation:

Given

Points: (1, 9) and (9, 3)

Ratio = 2/3

Required

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Represent the ratio as ratio

Ratio = 2:3

The new coordinate can be calculated using

C = (\frac{mx_2 + nx_1}{n + m},\frac{my_2 + ny_1}{n + m})

Where

(x_1,y_1) = (1, 9)

(x_2, y_2) = (9, 3)

m:n = 2:3

Substitute these values in the equation above

C = (\frac{2 * 9 + 3 * 1}{3 + 2},\frac{2 * 3 + 3 * 9}{2 + 3})

C = (\frac{18 + 3}{5},\frac{6 + 27}{5})

C = (\frac{21}{5},\frac{33}{5})

Hence;

<em>The coordinates of the new center is </em>C = (\frac{21}{5},\frac{33}{5})<em></em>

7 0
3 years ago
What are the common factors of 35 and 60?
Ksivusya [100]
I think it is 5 !!!!!!!!!!!!!!

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3 years ago
Factor completely:<br><br> 7r^2− 64r + 64
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Answer:

7r^2-64r+64

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Step-by-step explanation:

8 0
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