Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so
3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w
3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2
2x+2x=4x
If it says five more than it means the 5 is after, and quantity of a number means it’s in parentheses so it would have to be C.
I assume you meant 
.
Reflecting across the x-axis would give 
.
Reflecting across the y-axis would give 
.
Answer:
f(5) = 26.672 which is option D
Step-by-step explanation:
From question, f(1) = 2 and f'(x)=√(x^3 + 6)
f(5) = f(1) + (5,1)∫ f'(x) dx
Integrating using the boundary 5 and 1;
f(5) = 2 + (5,1)∫√(x^3 + 6) dx
f(5) = 2 + 24.672
So f(5) = 26.672
