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The final temperature inside the container is 77.5°C
<h3>Solution ; </h3>
There are two heat transfers involved:
heat lost by bolt 1 + heat gained by bolt 2 = 0
-q(heat released by iron bolt) at higher temperature = q(heat gained by iron bolt) at lower temperature
-(cm)(T2-Treat higher temperature) = (cm)(T2-Tre at lower temperature)
-[0.450/(J/g-K) × m × (T2 -100°C)] = [0.450/(J/g-K) × m × (T2 -55°C)]
Or, -(T2 - 100°C) (T2 - 55°C) T2+T2 = 100°C + 55°C
Or, T2 = 155°C /2 = 77.5°C
<h3>What is Specific Heat ?</h3>
Specific heat is the amount of heat necessary to increase the temperature of one gram of a substance by one degree Celsius. Specific heat is often measured in calories or joules per gram per Celsius degree. Water, for example, has a specific heat of one calorie (or 4.186 joules) per gram per Celsius degree.
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It has six significant figures. You count the 0s that come at the end because it shows you it wasn't rounded.
Answer:
See below
Explanation:
Coefficient on Fe₃(PO₄)₂ is incorrect => such means sum of mass reactants does not equal sum mass of products. Violates Law of Conservation of Matter in chemical reactions.
Correct balance is ...
6LiBr + Fe₃(PO₄)₂ => 2Li₃PO₄ + 3FeBr₂