Cu + 2 AgNO₃ = 2 Ag + Cu(NO₃)₂
mole ratio:
1 mole Cu --------------> 2 moles Ag
? mole Cu --------------> 3.50 moles Ag
moles Cu = 3.50 x 1 / 2
moles Cu = 3.50 / 2
<span>= </span><span>1.75 moles</span>
Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
Answer:
3-methylcyclohexene
Explanation:
In gas chromatography, the compound with the lower boiling point will have shorter time in the gas phase, resulting in fewer theoretical plates and a decreased retention time. Once a product exits the column it is transferred to the graph after passing through a detector which picks up on the differing conductance of the carrier gas vs. the carrier gas and product
Answer:
3.3 mol HCl
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
120 g HCl
<u>Step 2: Identify Conversions</u>
Molar Mass of HCl - 36.5 g/mol
<u>Step 3: Convert</u>
<u /> = 3.28767 mol HCl
<u>Step 4: Check</u>
<em>We are given 2 sig figs as our lowest. Follow sig fig rules and round.</em>
3.28767 mol HCl ≈ 3.3 mol HCl
Answer:
n=6 to n=3 (B)
Explanation:
Energy of an electron present in the orbit is directly proportional to .Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to .So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).