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lina2011 [118]
3 years ago
11

Mrs. Clark has a glass vase with a base shaped like a hexagon, as shown. The vase is 30 cm tall and the hexagon base has an area

of 64.5 cm2. How much water can Mrs. Clark’s vase hold? 94.5 cm2 964.5 cm2 645 cm3 1,935 cm3
Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Answer:

it is really ezzzy it is 1935

Step-by-step explanation:

u just have to do the math in your head or a paper it is easier an paper

Lisa [10]3 years ago
4 0

Answer: The correct option is fourth, i.e., 1935 cm³.

Explanation:

It is given that the vase is 30 cm tall and the hexagon base has an area of 64.5 cm².

The area of a hexagon base is,

A=\frac{3\sqrt{3}} {2}a^2

Where, a is the side length.

The volume of the a hexagon glass is,

V=\frac{3\sqrt{3}} {2}a^2\times h

V=A\times h

Where, A is area of base of hexagon and h is height of the hexagon glass.

V=64.5\times 30

V=1935

Therefore the volume of the glass is 1935 cm³ and the glass can hold 1935 cm³ water. So, fourth option is correct.

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To find the slope of the above equation, it is easiest to put it into slope-intercept form, y=mx + b, where the variable m represents the slope. To do this, we must isolate the variable y on the left side of the equation by using the reverse order of operations. First, we should subtract 3x from both sides of the equation.

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Next, we should divide both sides of the equation by 6 to undo the coefficent of 6 on the variable y.

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Hope this helps!

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<span> hope it helps</span>

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borishaifa [10]

Answer:

x = e^2/2 + 3

Step-by-step explanation:

Solve for x:

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Hint: | Eliminate the logarithm from the left hand side.

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8 0
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Read 2 more answers
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