Product A is increasing because the base 1.03 in the exponential is greater than 1.
The percent increase is
per year.
For product B, the rate of increase is
The percent increase is
per year.
Product A has a higher percent increase.
Let be
p(x)=<span>(x^{2} -1
q(x)=</span><span>3(x+1)
r(x)=1
the three coefficients of the equation
a is a singular point of the equation if lim p(x) =0
x------>a
so let's find a
</span> lim p(x) = lim x²-1=a²-1=0
x------>a x------>a
a²-1=0 implies a=+ or -1
so the sigular points are a= -1 or a=1
case 1
for a= -1
lim (x-(-1)) q(x)/p(x)=lim (x+1) 3(x+1)/x²-1=lim3(x+1)/x-1= 0/-2=0
x------> -1 x------> -1 x------> -1
lim (x-(-1))² r(x)/p(x)= lim(x+1)²/x²-1= 0/-2=0
x------> -1 x------> -1
lim (x-(-1)) q(x)/p(x) and lim (x-(-1))² r(x)/p(x) are finite so -1 is regular
x------> -1 x------> -1
singular point
case 2
a=1
lim (x-1)) q(x)/p(x)=lim (x-1) 3(x+1)/x²-1=lim3(x+1)/x+1= 3
x------> 1 x------> 1 x------> 1
lim (x-1))² r(x)/p(x)= lim(x-1)²/x²-1= =0
x------> 1 x------> 1
1 is also a regular singular point
Answer:
B is the answer to your question!
Answer:
is the closest to 8
Step-by-step explanation:
Answer:
The probability is 0.8
Step-by-step explanation:
The key to answering this question is considering the fact that the two married employees be treated as a single unit.
Now what this means is that we would be having 8 desks to assign.
Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!
Now, the number of ways the couple can interchange their desks is just 2 ways
Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)
The number of ways to assign desks among all six employees randomly is 9!
Thus, the probability that the couple will have adjacent desks would be ;
2(8!)/9! = 2/9
This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778
Which is 0.8 to the nearest tenth of a percent
