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UkoKoshka [18]
3 years ago
6

How to erite a sequence of 1/4 , 1/2,3 write a rule for the sequence 1/4 1/2 3/4

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0
The equation for finding the equation of an arithmetic sequence is an=a1+(n-1)d, where n is the input for the sequence, a1 is the first term, and d is the difference between each term. 

a1= 1/4
d= 1/4 

an= 1/4 + (n-1)(1/2) - First you need to distribute the 1/2 to both the n and -1 to get:    an= 1/4 + 1/2n -1/2.

Then you need to add like terms (1/4-1/2) to get an=1/2n-1/4.  Hope this helps!
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John was visiting four cities that form a rectangle on a coordinate grid at A(0, 4), B(4, 2), C(1, -4) and D(-3, -2). What is th
allsm [11]

Answer:

Area = 30

Step-by-step explanation:

Given

Rectangle coordinates

A = (0,4)

B = (4,2)

C = (1,-4)

D =(-3,-2)

Required

The area of the rectangle

The area is calculated as:

Area = Length* Width

The length of the rectangle will be represented as:

Length = AB = CD

And the width is:

Width = BC = AD

Calculate distance AB using:

AB = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

Where:

A = (0,4) --- (x_1,y_1)

B = (4,2) --- (x_2,y_2)

AB = \sqrt{(0 - 4)^2 +(4 - 2)^2 }

AB = \sqrt{(- 4)^2 +(2)^2 }

AB = \sqrt{16 +4 }

AB = \sqrt{20}

Calculate distance BC using:

BC = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

C = (1,-4) ---(x_1,y_1)

B = (4,2) --- (x_2,y_2)

BC = \sqrt{(1 - 4)^2 +(-4 - 2)^2 }

BC = \sqrt{(- 3)^2 +(-6)^2 }

BC = \sqrt{9 +36}

BC = \sqrt{45}

So, the area is:

Area = Length * Width

Area = AB * BC

Area = \sqrt{20} * \sqrt{45}

Area = \sqrt{20 * 45}

Area = \sqrt{900

Area = 30

4 0
3 years ago
Anyone know the answer the answer to this algebra 2 question? Anyone that gets it will give brainiest
viktelen [127]

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3 0
3 years ago
Read 2 more answers
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Andreas93 [3]

Answer:

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Step-by-step explanation:

3x-4y=242

substitute y = 0

3x-4x0=242

calculate the product

3x-0=242

remove 0

3x=242

divide both sides (by 3 in order to leave x by itself)

done

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3 years ago
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lara31 [8.8K]
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So 3x3 = 9
And 4x4 = 16
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And the square root of 25 is 5

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