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masya89 [10]
3 years ago
7

John was visiting four cities that form a rectangle on a coordinate grid at A(0, 4), B(4, 2), C(1, -4) and D(-3, -2). What is th

e area of the space that cities enclose? Round your answer to the nearest whole number. Do not include units in your answer.
Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:

Area = 30

Step-by-step explanation:

Given

Rectangle coordinates

A = (0,4)

B = (4,2)

C = (1,-4)

D =(-3,-2)

Required

The area of the rectangle

The area is calculated as:

Area = Length* Width

The length of the rectangle will be represented as:

Length = AB = CD

And the width is:

Width = BC = AD

Calculate distance AB using:

AB = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

Where:

A = (0,4) --- (x_1,y_1)

B = (4,2) --- (x_2,y_2)

AB = \sqrt{(0 - 4)^2 +(4 - 2)^2 }

AB = \sqrt{(- 4)^2 +(2)^2 }

AB = \sqrt{16 +4 }

AB = \sqrt{20}

Calculate distance BC using:

BC = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

C = (1,-4) ---(x_1,y_1)

B = (4,2) --- (x_2,y_2)

BC = \sqrt{(1 - 4)^2 +(-4 - 2)^2 }

BC = \sqrt{(- 3)^2 +(-6)^2 }

BC = \sqrt{9 +36}

BC = \sqrt{45}

So, the area is:

Area = Length * Width

Area = AB * BC

Area = \sqrt{20} * \sqrt{45}

Area = \sqrt{20 * 45}

Area = \sqrt{900

Area = 30

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