4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =

y = -x
<span>
Thus the gradient of the two equations are different and as such the two lines are not parallel</span>
B) When two lines are perpendicular, the product of their gradient is -1

p = (-2) * (-1)
p = 2
<span> ∴
the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
Those are positive numbers.
Those that are less than zero are called negative numbers.
Zero itself can be considered both, or neither.
30-f+8f=30
30+7f=30
Move +30 to the right side. Sign changes from +30 to -30.
30-30+7f=30-30
7f=0
Divde by 7
7f/7=0/7
Cross out 7 and 7, divide by 7. Becomes 1*1*f=f
f=0
Answer: f=0
Answer:
Step-by-step explanation:
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
To solve the problem find the value of (45)^2 at first


The answer is 25 with the remainder 75

You can simplify the fraction to be 25/26