Answer:
it would take about 7 1/2 minutes.
Step-by-step explanation:
please give brainliest
The first thief takes (1/2 x + 1) . What remains ? x - (1/2x + 1)
So the 2nd thief takes 2/3 of [ x - (1/2x + 1) ]
What remains ? x - 2/3 [ x - (1/2x + 1) ]
So the 3rd thief takes 2/3 of { x - 2/3 [ x - (1/2x + 1) ] } and he takes 1 more .
What remains ? x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )
And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..
The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.
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This is a lot harder than just solving the problem with logic and
waving your hands in the air. Here's how you would do that:
Start from the end and work backwards:
-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.
Thank you for your generous 5 points.
Answer:
The bracelet will cost 85$ and it'll have 2 charms.
Step-by-step explanation:
In order to find the total cost of the bracelet and how many charms it'd be we need to build an equation for each store. So we have:
Oak Grove:
total cost = 16*charm + 53
Sandoval:
total cost = 27*charm + 31
We then find the number of charm that'll make them equal, since the price has to be the same on both shops:
16*charm + 53 = 27*charm + 31
27*charm - 16*charm = 53 - 31
11*charm = 22
charm = 2
The cost of the bracellet is:
total cost = 27*2 + 31 = 85 $
It's called a decimal.
I hope it helps.
