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Zina [86]
4 years ago
9

What is this math problem

Mathematics
2 answers:
Over [174]4 years ago
6 0
Well, I don't have an answer but I have something that will help. Find the hemisphere then the rectangle then find both the triangles and add it together!!!
fgiga [73]4 years ago
4 0
40×5+12 is ur. equaio
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Please help will mark brainiest plz make sure it’s right and NO links or anything like that! :)
Mariulka [41]
Use the given functions to set up and simplify
h(8). The answer is −22. Hope this help! :)
8 0
3 years ago
Read 2 more answers
Questions Below. Would Appreciate Help!
kherson [118]

Answer:

The function that could be the function described is;

f(x) = -10 \cdot cos \left (\dfrac{2 \cdot \pi }{3} \cdot x \right ) + 10

Step-by-step explanation:

The given parameters of the cosine function are;

The period of the cosine function = 3

The maximum value of the cosine function = 20

The minimum value of the cosine function = 0

The general form of the cosine function is presented as follows;

y = A·cos(ω·x - ∅) + k

Where;

\left | A \right | = The amplitude = Constant

The period, T = 2·π/ω

The phase shift, = ∅/ω

k = The vertical translation = Constant

Therefore, by comparison, we have;

T = 3 = 2·π/ω

∴ ω = 2·π/3

The range of value of the cosine of an angle are;

-1 ≤ cos(θ) ≤ 1

Therefore, when A = 10, cos(ω·x - ∅) = 1 (maximum value of cos(θ)) and k = 10, we have;

y = A × cos(ω·x - ∅) + k

y = 10 × 1 + 10 = 20 = The maximum value of the function

Similarly, when A = 10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, we get;

y = 10 × -1 + 10 = 0 = The minimum value of the function

Given that the function is a reflection of the parent function, we can have;

A = -10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, to get;

y = -10 × -1 + 10 = 20 = The maximum value of the function

Similarly, for cos(ω·x - ∅) = 1 we get;

y = -10 × 1 + 10 = 0 = The minimum value of the function

Therefore, the likely values of the function are therefore;

A = -10, k = 10

The function is therefore presented as follows;

y = -10 × cos(2·π/3·x) + 10

8 0
3 years ago
-4+3b^2=143<br><br> Simplest radical form
Karolina [17]

Answer:

- 4 + 3b {}^{2 }  = 143 \\ 3b {}^{2}  = 143 + 4 \\ 3b {}^{2} = 147 \\ b {}^{2}   =  \frac{147}{3}  \\ b {}^{2}  = 49 \\ b = 7

3 0
3 years ago
In 1986, the worst nuclear disaster occurred in Chernobyl, USSR, when an explosion at a nuclear power plant released 1000 kg of
Lostsunrise [7]

Considering the function for the remaining amount of cesium in the atmosphere, F(x) = 1000×0.5^(x/30), we have;

First part:

  • The area will be safe again in about 100 years time.

Second part;

  • The y-intercept is at the start of the measurement

Third part;

  • The function is a decay function

<h3>Which method can be used to evaluate the given function?</h3>

First part;

The given function for the remaining amount of cesium is presented as follows;

F(x) = 1000 \times  {0.5}^{ \frac{x}{30} }

When 100 kg. of cesium is remaining, we have;

100= 1000 \times  {0.5}^{ \frac{x}{30} }

Which gives;

\frac{x}{30}  =  \frac{ log(0.1) }{ log(0.5) }

x=  \frac{ log(0.1) }{ log(0.5) }  \times 30 \approx  100

  • Therefore, the area will be safe again in approximately 100 years.

Second part;

The y-intercept is given by the point where <em>x </em>= 0

At the y-intercept, we therefore have;

F(0) = 1000 \times  {0.5}^{ \frac{0}{30} }

  • F(0) = 1000

At the y-intercept, the amount of cesium remaining, F(x) is 1,000, which is the initial amount of cesium.

  • The y-intercept is therefore, at the start of the measurement, where 1000 kg. is present in the atmosphere.

Third part;

The amount of cesium remaining F (x) decreases as the time, <em>x</em>, increases, the function is therefore a decay function.

Learn more about exponential functions here;

brainly.com/question/2456547

#SPJ1

8 0
2 years ago
the Millers, Rigbys, and the Smiths went on a camping trip. The Millers spent $100 more then Rigbys, and the Smiths spent twice
KATRIN_1 [288]

Let  \: x \:  be \:  the  \: money  \: the \:  Millers \:  spent \\ The  \: Rigbys  \: spent:x-100 \\ The  \: Smiths \:  spent:2x \\ We  \: have  \: an \:  equation:x + x - 100 + 2x = 580 \\  <  =  > 4x = 680 \\   <  =  > x = 170 =  > 2x = 340 \\ So \:  the \:  Smiths  \: spent \: \$340

8 0
3 years ago
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