What is this math problem

Mathematics

2 answers:

Over [174]3 years ago

6 0

Well, I don't have an answer but I have something that will help. Find the hemisphere then the rectangle then find both the triangles and add it together!!!

fgiga [73]3 years ago

4 0

40×5+12 is ur. equaio

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Let a = 0.9876 and b = 0.9887 with N = 2, calculate the midpoint.

rodikova [14]

Answer:

For a=0.9876 and b=0.9887 mid point will be 0.98815

Step-by-step explanation:

We have given a = 0.9876 and b = 0.9887

And N = 2

We have to find the mid point

For finding mid point we know that formula

Midpoint $=\frac{a+b}{2}$ , here we have given a=0.9876 and b = 0.9887

So midpoint will be $=\frac{0.9876+0.9887}{2}=\frac{1.9763}{2}=0.98815$

So for a=0.9876 and b=0.9887 mid point will be 0.98815

5 0

3 years ago

A triangle has angle measurements of 61°, 84°, and 35°. is this triangle isosceles?

ch4aika [34]

Answer: No

Step-by-step explanation:

This is not an isosceles triangle because there are different angle measurements. The rule of an isosceles triangle is that it must always have two equal sides and angles.

8 0

2 years ago

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

Anika [276]

For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4

Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1

Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20

Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3

6 0

2 years ago

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=41°, and SQ = 94 feet. Find the length of QR to the nearest tenth of a foot.

timama [110]

Answer:

124.6

Step-by-step explanation:

maths

6 0

2 years ago

Laura goes to a bank and opens a new account. She deposits $5,500. The bank pays 1. 6% interest compounded annually on this acco

HACTEHA [7]

The amount that is the closest to the account balance at the end of 4 years is given by: Option B: $5,860. 53 (approx)

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$CI = P(1 +\dfrac{R}{100})^T - P$