A man is 61 5/12 inches tall and his daughter is 58 4/9 inches tall. How much taller is the man?

Mathematics

1 answer:

777dan777 [17]2 years ago

7 0

Given:

Height of a man = $61\dfrac{5}{12}$ inches

Height of the daughter = $58\dfrac{4}{9}$ inches

To find:

How much taller is the man?

Solution:

It this problem, we need to find the difference between the heights of the man and his daughter.

Difference between the heights $=61\dfrac{5}{12}-58\dfrac{4}{9}$

$=\dfrac{732+5}{12}-\dfrac{522+4}{9}$

$=\dfrac{737}{12}-\dfrac{526}{9}$

Taking LCM, we get

Difference between the heights $=\dfrac{3(737)-4(526)}{36}$

$=\dfrac{2211-2104}{36}$

$=\dfrac{107
}{36}$

$=2\dfrac{35
}{36}$

Therefore, the man is $2\dfrac{35}{36}$ inches taller than his daughter.

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