Question

A man is 61 5/12 inches tall and his daughter is 58 4/9 inches tall. How much taller is the man?

Answer 1

Given:

Height of a man = $61\dfrac{5}{12}$ inches

Height of the daughter = $58\dfrac{4}{9}$ inches

To find:

How much taller is the man?

Solution:

It this problem, we need to find the difference between the heights of the man and his daughter.

Difference between the heights $=61\dfrac{5}{12}-58\dfrac{4}{9}$

                                                      $=\dfrac{732+5}{12}-\dfrac{522+4}{9}$

                                                      $=\dfrac{737}{12}-\dfrac{526}{9}$

Taking LCM, we get

Difference between the heights $=\dfrac{3(737)-4(526)}{36}$

                                                      $=\dfrac{2211-2104}{36}$

                                                      $=\dfrac{107 }{36}$

                                                      $=2\dfrac{35 }{36}$

Therefore, the man is $2\dfrac{35}{36}$ inches taller than his daughter.