X^2+12x=0
(ax^2+bx)=0
(b/2)^2=(12/2)^2=(6)^2=36
x^2+12x+36=(x+6)^2
Answer:
Given
x+y+z=0
⟹x+y=−z
Cubing on both sides
(x+y) 3 =(−z) 3
⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3
⟹x 3 +y 3 +3xy(x+y)=−z 3
⟹x 3+y 3+3xy(−z)=−z 3
⟹x 3 +y 3−3xyz=−z 3
⟹x 3 +y 3 +z 3 =3xyz
Step-by-step explanation:
Hope it is helpful.....
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
