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alisha [4.7K]
1 year ago
6

Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0​

Mathematics
1 answer:
Westkost [7]1 year ago
8 0

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

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tester [92]

Answer:

Step-by-step explanation:

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r_1= 1^2

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you do your math!!

7 0
2 years ago
I need help with this work
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Answer:

no

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m=18

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4 0
3 years ago
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8 0
3 years ago
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Which is the most efficient method?
marysya [2.9K]
Hello! 

The answer to your question is A. Elimination.

Have a good day! -Wajiha
8 0
3 years ago
ranslate the sentence into an equation using n as the unknown number. Then solve the equation for n. Two times a number increase
joja [24]
Hi there!

Let's break this down:
Two times a number = 2n
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is 15 - = 15

Total equation:
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Solving:
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n = 5

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
4 0
3 years ago
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