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krok68 [10]
3 years ago
11

The pyramid shown has a square base that is 24 inches on each side. The slant height is 20 inches. What is the surface area of t

he pyramid?
Mathematics
1 answer:
kondaur [170]3 years ago
7 0

Answer:

Surface area of pyramid = 1536 square inches.

Step-by-step explanation:

Surface area of a pyramid with the square base will be = surface area of base + 4× slant surfaces of the pyramid

area of square base = 24×24 = 576 inches²

area of one slant side of pyramid = (1/2)×side × slant height = (24×20)/2 = 240 square inches

Therefore surface area of complete pyramid = 4×area of slant side + surface area of square base = 4×240 + 576 = 960 + 576 = 1536 square inch.

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<span> AA3 + 2 = AAA
CC6 + 6 = CBB
(AB | C) -> S57 -> E73-> S47-> E57-> S43-> W26-> S18->? </span>
Task: Find out the coordinates where Mark should come.<span> "

First, you need to solve for the position from which Mark starts. 
You know: 
</span><span>AA3 + 2 = AAA
Since 3 + 2 = 5,
553 + 2 = 555
Therefore A = 5.

Similarly: 
</span><span>CC6 + 6 = CBB 
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In order from the middle digit to be 2, the original one must have been 1.
Therefore B = 2 and C = 1

Hence, the starting position is: (AB, C) = (52, 1)

The following line gives you how many steps and in what direction Mark should go: S = south (negative vertical motion), N = north (positive vertical motion), E = east (positive horizontal motion), W = west (negative horizontal motion).

(52, 1) 
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-> S47 -> (125, -103)
-> E57 -> (182, -103)
-> S43 -> (182, -146)
-> W26 -> (156, -146)
-> S18 -> (156, -164)

Hence, the coordinates that Mark should reach are (156, -164)
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