Please help and no links to stuff bc they don't work

What is the answer A. B. C. D.

RUDIKE [14]

Answer:

B.

Step-by-step explanation:

The opposite of 5/2 is -5/2 which is -2 1/2 and the opposite of -1/2 is 1/2.

4 0

2 years ago

Which of the following inequalities matches the graph A) x > -3 B) X< -3 C) y > -3 D) y < -3

lara [203]

Can you take a picture of the graph?

5 0

3 years ago

Read 2 more answers

A triangular park has sides 80m, 64m and 48m.

KatRina [158]

Answer:

plz type the full question ,.......or this is the full question.....

4 0

3 years ago

Read 2 more answers

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

Gibson Instruments is planning to produce and market a new line of guitars. The current market price for similar guitars is $1,2

m_a_m_a [10]

We are given the current market price that is $1,200 and we are asked in the problem to compute the target cost if one wishes to gain a 30% profit. In this case, we have to minimize the cost to achieve the profit desired. Then,

1.3 y = 1200
where y is the target cost
y = $923.08

5 0

4 years ago

Please help and no links to stuff bc they don't work ​

Please help and no links to stuff bc they don't work