Answer:
I apologize if this was poorly explained. The explanation for each is below the angle.
Since these triangles are in a rectangle, The top and bottom triangles are congruent, and the left and right triangles are congruent. All 4 triangles are also Isosceles. (Two equal sides/angles)
m<1= 59
(Left and right triangles are congruent)
m<2=31
(Top and bottom triangles are congruent)
m<3= 59
(Directly across from the other 59)
m<4=31
(Each of the rectangles corner angles totals to 90 degrees, therefore making this angle 31 degrees.)
m<5=31
(Since the triangles are isosceles, this angle is also 31)
m<6= 59
(Since m<5 is 31, this angle is 59.)
m<7=118
{(Two other angles in the triangle) 31+31= 62 180-62= 118)}
m<8=62
{(Two other angles in the triangle)59+59= 118. 180-118= 62}
m<9=62
(This angle and m<8 are congruent.)
m<10=118
(This angle and m<7 are congruent.)
m<11=31
(Same reason as m<4)
I hope this helps!
Answer:
The answer is
<h2>p > 1/14</h2>
Step-by-step explanation:
-31p+79 > -59p+81
Group like terms
Send the constants to the right side of the expression and those with variables to the left side
That's
- 31p + 59p > 81 - 79
Simplify
We have
28p > 2
Divide both sides by 28
We have the final answer as
<h3>p > 1/14</h3>
Hope this helps you
Answer:
you just have to multiply and subtract or divide and give you the answer
Step-by-step explanation:
i you wan i can do them for you
Start with #47. To find the critical values, you must differentiate this function. x times (4-x)^3 is a product, so use the product rule. The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x]
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of f '(x) = (4-x)^2 [-3x+4-x]. (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1. Thus, the "cv" are {4,1}.
Evaluate the given function at x: {4,1}. For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8. Thus, one of the extreme values is (1,8).
