1 and one - twelfth
because 12gies 3 times in 37
X = 2
y = 3
You can simply set these two equal to each other and solve for x. Then plug in to find y.
Given that Audra was drawing a perpendicular bisector of segment AB with a compass. She started with line segment AB. Then, she placed her compass point on A and opened the compass more halfway to B.
Her next step will be "Using the width of the compass from the previous step, draw two arcs to the left and right of both A and B".
Problem 1
The Blue Jays had the most passing yards. Circle the "passing" column, which is column 1. Then look for the largest value in this column. This largest value is 108 which belongs to the Blue Jays.
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Problem 2
The answer is choice B. To get this answer, you multiply every value inside the matrix by -5
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
