The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
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Answer:
d
Step-by-step explanation:
FV = P (1 + r/m)^mn
FV = Future value
P = Present value
R = interest rate
N = number of years
m = number of compounding
a. 6000x (1 + 0.04/12)^24 = 6498.86
b. . 6000x (1 + 0.03/12)^36 =6564.31
c. . 6000x (1 + 0.01/12)^48 = 6244.76
d. . 6000x (1 + 0.05/12)^60 =6630.47
There has to be something in between the two numbers, for example 7 x 7 or 7+7 not just 7 7. Without the equation it would be highly impossible to answer :D
An exponential decay function goes down to the right, like in the picture attached.
An exponential function follows this format: 
, where b is less than 1 and more than 0. b is more than 0 but less than 1 in function A.
