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laila [671]
3 years ago
11

What is the decay factor of the exponential function represented by the table? One-third Two-thirds 2 6

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

Answer:

2/3

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
6 0

Answer:

the second one i believe

Step-by-step explanation:

hope this helps :)

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Area = 140

16 x 8.75 = 140

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4 0
3 years ago
See question in screenshot below.
alexgriva [62]

The equation of the transformation of the exponential function <em>y</em> = 2ˣ in the form <em>y</em> = A·2ˣ + k, obtained from the simultaneous found using the points on the graph is <em>y</em> = (-2)·2ˣ + 3

<h3>What is an exponential equation?</h3>

An exponential equation is an equation that has exponents that consists of variables.

The given equation is <em>y</em> = 2ˣ

The equation for the transformation is; <em>y</em> = A·2ˣ + k

The points on the graphs are;

(0, 1), (1, -1) and (2, -5)

Plugging the <em>x </em>and <em>y</em>-values to find the value <em>A</em> and <em>k</em> gives  the following simultaneous equations;

When <em>x</em> = 0, <em>y</em> = 1, therefore;

1 = A·2⁰ + k = A + k

1 = A + k...(1)

When <em>x</em> = 1, <em>y</em> = -1, which gives;

-1 = A·2¹ + k

-1 = 2·A + k...(2)

Subtracting equation (1) from equation (2) gives;

-1 - 1 = 2·A - A + k - k

-2 = A

1 = A + k, therefore;

1 = -2 + k

k = 2 + 1 = 3

k = 3

Which gives;

y = -2·2ˣ + 3 = 3 - 2·2ˣ

Learn more about the solutions to simultaneous equations here:

brainly.com/question/26310043

#SPJ1

3 0
1 year ago
Help please:):(“/$)
Andrews [41]

1. Distance between points is 7

2. Distance between points is 6

3. Distance between points is 10

4. Distance between points is 6

5. Distance between points is 4

4 0
3 years ago
(1,-6,); (9,-8)<br> Slope <br><br><br><br><br> Best answer =branniest
nignag [31]
Answer:-1/4

Why? Slope=rise/run and can be found with the difference of y over the difference of x
-8- -6= -2
9-1= 8
so the slope is -2/8 but you have to simplify so you get
-1/4

Hope this helps
6 0
3 years ago
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