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2 years ago

1. Draw a quadrilateral with 2 parallel sides. It should have 2 pairs of perpendicular lines.

Mathematics

1 answer:

Elenna [48]2 years ago

5 0

Answer:

draw a rectangle

Step-by-step explanation:

a rectangle has 2 long sides and 2 short ones it has 2 sets of simailer and has 2 perpundicular

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Dr. Gilmore's research group tagged and released 800 squirrels for a study of a local park. Later, they trapped 430 squirrels, 4

Mrrafil [7]

Using proportions, it is found that the best estimate for the squirrel population is of 8000.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, 43 squirrels out of 430 had tags. Considering that in the entire population, 800 are tagged, and we want to find the total population, the rule of three is given by:

43 tagged - 430 squirrels

800 tagged - x squirrels

Applying cross multiplication:

$43x = 430 \times 800$

$x = \frac{430 \times 800}{43}$

$x = 8000$

The best estimate for the squirrel population is of 8000.

More can be learned about proportions at brainly.com/question/24372153

8 0

2 years ago

If you bought a hamburger for $2.30 and paid for it with a 5 dollar bill, how much change would you receive?

daser333 [38]

You would get $3.70

4 0

3 years ago

Read 2 more answers

How do I solve this?<br><br> -6x-1+5x^2 = 8x^2<br><br> Thanks

max2010maxim [7]

Answer:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Or, by approximating:

$x\approx-0.1835\text{ or } x\approx -1.8165$

Step-by-step explanation:

Let’s convert this to standard form. We have:

$-6x-1+5x^2=8x^2$

Subtract 5x² from both sides:

$-6x-1=3x^2$

And add 6x and 1 to both sides:

$0=3x^2+6x+1$

This is not factorable. So, we will need to use the quadratic formula.

The quadratic formula for a quadratic in standard form is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}$

In this case, a=3; b=6, and c=1.

Substitute appropriately:

$\displaystyle x=\frac{-6\pm\sqrt{6^2-4(3)(1)}}{2(3)}$

Simplify:

$\displaystyle x=\frac{-6\pm\sqrt{24}}{6}$

We can simplify the square root:

$\sqrt{24}=\sqrt{4}\cdot\sqrt{6}=2\sqrt{6}$

Hence:

$\displaystyle x=\frac{-6\pm2\sqrt{4}}{6}$

Simplify:

$\displaystyle x=\frac{-3\pm\sqrt{6}}{3}$

Hence, we will have two solutions:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Approximating them, we can see that our solutions are approximately:

$x\approx-0.1835\text{ or } x\approx -1.8165$

7 0

3 years ago

I need help please and thank you

RideAnS [48]

Answer:

Gold

Step-by-step explanation:

Just google it... but yeah you're welcome

3 0

3 years ago

81x^6-x^2 simplify the expression

Sophie [7]

First you need to factor out the common term $x^{2}$
Which would be $x^2\left(81x^4-1\right)$
And so the answer is $x^2\left(81x^4-1\right)$

Hope this helps.

6 0

4 years ago

1. Draw a quadrilateral with 2 parallel sides. It should have 2 pairs of perpendicular lines. ​

1. Draw a quadrilateral with 2 parallel sides. It should have 2 pairs of perpendicular lines.