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Vladimir [108]
2 years ago
12

1. Draw a quadrilateral with 2 parallel sides. It should have 2 pairs of perpendicular lines. ​

Mathematics
1 answer:
Elenna [48]2 years ago
5 0

Answer:

draw a rectangle

Step-by-step explanation:

a rectangle has 2 long sides and 2 short ones it has 2 sets of simailer and has 2 perpundicular

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What is the equation of the line in point slope form
Phoenix [80]
Well... to solve use rise over run... that is to find the slope,
now to find the y-intercept you look at what coordinate crosses the y-axis. 
y= (what you got for the slope Ex. 1/2)x + (the y-intercept)

Figure it out and you got the answer with just a bit of help!!!

Hope this helps!
5 0
3 years ago
Gcf of 6w square - 14w
melamori03 [73]
GCF of them is 2w.

Hope this helps :)
7 0
3 years ago
The second of two numbers is 3 less than twice the first. Their sum is 36. Find the numbers.
o-na [289]

Answer:

13 and 23

Step-by-step explanation:

create an equation to solve:

(2x-3) + x = 36

3x - 3 = 36 combine like terms

<u> +3 +3</u><u> </u> add 3 to both sides

<u>3</u>x = <u>39</u>

3 3 divide both sides by 3

x = 13

<u>13 is the first number</u>

the 2nd number is 3 let than twice the first so we create and solve a new equation:

2x - 3 = ?

2(13) = ? substitute 13 from the

smaller number to solve

<u>23 = the 2nd number</u>

3 0
4 years ago
What's the answer to 4+7(-10n-5)
strojnjashka [21]
What you would do is -10+5=-5 then you add 4+7= 11 then you mutiply them answers together 11*-5=-55 hope this helps you
8 0
3 years ago
Help !! Please I can’t find the answer
SVETLANKA909090 [29]

Answer:

\large\boxed{r^2=(x+5)^2+(y-4)^2}

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}

The radius:

r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4

(-5,\ 4)\to h=-5,\ k=4

Finally:

(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13

5 0
3 years ago
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