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3 years ago

At the hairdresser, Jenny had 27 centimeters cut off her hair. How many decimeters of hair did Jenny have cut off?

Mathematics

2 answers:

Fynjy0 [20]3 years ago

8 0

Since a centimeter is equal to 0.1 decimeter, the answer would be 2.7 centimeters

lions [1.4K]3 years ago

3 0

1 centimetre=0.1 decimetre
therefore the answer is 2.5 decimetres.

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The total area of both plots of land is?

VikaD [51]

You have 2x^2 + 9x -9 and 3x^2 -2x +14

To find total area add the two polynomials together by combining the like terms.

2x^2 + 3x^2 = 5x^2

9x + -2x = 9x-2x = 7x

-9 + 14 = 5

Total area = 5x^2 + 7x + 5

7 0

3 years ago

What is the x- intercept of y+ 12 =3 (x-9)?

Natalija [7]

Answer:

13,0

Step-by-step explanation:

12=3(x-9)

divide both sides by three

4=x-9

add 9 to both sides

x=13

so, the x intercept is (13,0)

7 0

2 years ago

Read 2 more answers

The hypotenuse of a 45°-45°-90° triangle measures 18 cm. What is the length of one leg of the triangle?

lara31 [8.8K]

Answer:

The legs of a 45 45 90 triangle are congruent so if one leg is x we can write (using the Pythagorean Theorem):

x² + x² = 18²

2x² = 324

x² = 162

x = 9√2

4 0

3 years ago

What is the measure of Zx?<br> X= ??

Montano1993 [528]

Answer:

x = 31 degrees

Step-by-step explanation:

180 - 149 = 31

Hope this helps!

3 0

3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

2 years ago