Answer:
Children ticket cost $30 and adult ticket costs $40.
Step-by-step explanation:
Given that:
x = price of a child ticket
y = price of an adult ticket
According to given statement;
3x+2y=170 Eqn 1
4x+6y=360 Eqn 2
Multiplying Eqn 1 by 3
3(3x+2y=170)
9x+6y=510 Eqn 3
Subtracting Eqn 2 from Eqn 3
(9x+6y)-(4x+6y)=510-360
9x+6y-4x-6y=150
5x=150
Dividing both sides by 5
Putting x=30 in Eqn 1
3(30)+2y=170
90+2y=170
2y = 170-90
2y = 80
Dividing both sides by 2
Hence,
Children ticket cost $30 and adult ticket costs $40.
Sent a picture of the solution to the problem (s).
Answer:
x = y = 22
Step-by-step explanation:
It would help to know your math course. Do you know any calculus? I'll assume not.
Equations
x + y = 44
Max = xy
Solution
y = 44 - x
Max = x (44 - x) Remove the brackets
Max = 44x - x^2 Use the distributive property to take out - 1 on the right.
Max = - (x^2 - 44x ) Complete the square inside the brackets.
Max = - (x^2 - 44x + (44/2)^2 ) + (44 / 2)^2 . You have to understand this step. What you have done is taken 1/2 the x term and squared it. You are trying to complete the square. You must compensate by adding that amount on the end of the equation. You add because of that minus sign outside the brackets. The number inside will be minus when the brackets are removed.
Max = -(x - 22)^2 + 484
The maximum occurs when x = 22. That's because - (x - 22) becomes 0.
If it is not zero it will be minus and that will subtract from 484
x + y = 44
xy = 484
When you solve this, you find that x = y = 22 If you need more detail, let me know.
When
|a|=b
assume
a=b and -a=b
so
4+|7-m|=5
minus 4 from both sides
|7-m|=1
assume
7-m=1 and
-(7-m)=1
7-m=1
minus 7 both sidees
-m=-6
times -1 both sides
m=6
-(7-m)=1
distribute
-7+m=1
add 7 to both sides
m=8
m=6 and 8
