Answer:
Step-by-step explanation:
4 times 4 is 16 so while both are in power so we can do this like that
. The coach splits a team of 27 students into 3 groups to practice skills. How many c
2 answers:
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( + 4)(
- 4)
To solve this question you must FOIL (First, Outside, Inside, Last) like so
First:
(x^2 + 4)(x^2 - 4)
x^2 * x^2
x^4
Outside:
(x^2 + 4)(x^2 - 4)
x^2 * -4
-4x^2
Inside:
(x^2 + 4)(x^2 - 4)
4 * x^2
4x^2
Last:
(x^2 + 4)(x^2 - 4)
4 * -4
-16
Now combine all the products of the FOIL together like so...
x^4 - 4x^2 +4x^2 - 16
Combine like terms:
x^4 - 4x^2 +4x^2 - 16
- 4x^2 +4x^2 = 0
x^4 - 16 <<<This is your answer
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
(1) The possible outcomes are: X = {0, 1, 2, 3}.
(2) The number of times should Hartley spin a difference of 1 is 36.
(3) The number of times should Hartley spin a difference of 0 is 24.
Step-by-step explanation:
The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.
The total number of spins for each of the spinner is, <em>n</em> = 96.
(1)
The sample space of spinning both the spinners together are:
S = {(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)}
Total = 16.
The possible outcomes are:
X = {0, 1, 2, 3}.
(2)
The sample space with the difference 1 are:
S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}
n (S₁) = 6
The probability of the difference 1 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 1 is:
Thus, the number of times should Hartley spin a difference of 1 is 36.
(3)
The sample space with the difference 0 are:
S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}
n (S₂) = 4
The probability of the difference 0 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 0 is:
Thus, the number of times should Hartley spin a difference of 0 is 24.