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3 years ago

. The coach splits a team of 27 students into 3 groups to practice skills. How many c

Mathematics

2 answers:

MAXImum [283]3 years ago

8 0

Answer: 9 students

Step-by-step explanation:

To get the solution to this question, we will divide the 27 students into 3.

That is 27 ÷ 3

= 9, There will be 9 students per group.

I hope this is clear, please mark as brainliest answer.

Serga [27]3 years ago

5 0

Answer:

There is 9 students in each group :)

Step-by-step explanation:

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How do you turn .15 repeating into a fraction show work

mafiozo [28]

0.15 as a fraction would be 3 over 20 or 3/20. Hope this helps! Plz mark me as brainliest!!! :)

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3 years ago

A solid rectangular box with height 5 m and square base with side lengths 4 m is built using a lightweight material whose densit

elena55 [62]

Answer:

627200LJ

Step-by-step explanation:

Height of box=5 m

Side of square base=4 m

Volume of rectangular box= $l\times b\times h$

Using the formula

Volume of rectangular box= $4\times 4\times 5=80m^3$

Density of material= $800kg/m^3$

We know that

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Using the formula

Mass of rectangular box= $80\times 800=64000 kg$

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3 years ago

What does it mean when it says a shape has reflection symmetry?

brilliants [131]

It means that if you fold it in half the two halves will be the exact same

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3 years ago

PLEASE SOMEONE HELP ME!!! I'm stuck on this problem!!! (THE DIRECTION IS ---"Find the area of the figure")

svetlana [45]

A = 3,953 in²

You find the area of the whole triangle:
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Since you're multiplying inches by inches, it's inches².

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3 years ago

Read 2 more answers

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

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3 years ago