We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>
Answer:
hello
Step-by-step explanation:
ok so he had 120 brinjal plants 90 ladys finger plant 45 chilli plants
ok so a storm came along
120/12
90/3
45/29
i think its right if not im so sorrry
Answer:
The correct option is;
This statement is true
Step-by-step explanation:
The given transformation are;
1) Vertical translation, y units down
2) Horizontal translation x units right
Therefore, the equivalent transformation is 
Whereby the coordinates of the of the point on the preimage with the largest y-coordinates are (a, b), we have;
The coordinate of the corresponding point on the image = (a + x, b - y)
Given that the value of b is larger than the the y-coordinates values of al the points on the preimage, therefore, the value of b - y, will be the largest of the y-coordinates values on the image
