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Nesterboy [21]
3 years ago
6

Order the fraction to least to greatest 7\9 13\18 5\6 2\3

Mathematics
1 answer:
Olegator [25]3 years ago
7 0
First, you need to have a common denominator for all of them, in this case, they can all go in 18 so that will be the common denominator. 

\frac{7}{9} x \frac{2}{2} = \frac{14}{18}
\frac{5}{6} x \frac{3}{3} =  \frac{15}{18}
\frac{2}{3} x \frac{6}{6} = \frac{12}{18}
\frac{13}{18}

Now you can tell which ones are the biggest or smallest. So from least to greatest you would have this.

\frac{2}{3} , \frac{13}{18} , \frac{7}{9} , \frac{5}{6}

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F(x) = { x + 7 and g(x) = -x + 7<br> What transformation occurs from function f to function g?
Triss [41]
<h3>Answer:  Reflect over the y axis</h3>

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Explanation:

We have these two given functions

  • f(x) = x+7
  • g(x) = -x+7

The change is that the x has been replaced with -x

We can say

f(x) = x+7

f(-x) = -x+7 ... replace each x with -x

g(x) = f(-x)

g(x) = -x+7

When we replace x with -x, we're flipping the x inputs from positive to negative, and vice versa. This visually will reflect the line over the vertical y axis. A point like (1,8) on f(x) reflects over to (-1,8) on g(x).

As another example, the point (-5,2) on f(x) reflects over the y axis to arrive at (5,2) on the g(x) function.

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2 years ago
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Phantasy [73]

The height of the object after 1 sec is 284 feet

<h3>Equation of height of an object</h3>

Given the equation of height of an object expressed as:

h(t) = -16t^2 + 300t

We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression

h(t) = -16t^2 + 300t

h(1) = -16(1)^2 + 300(1)

h(1) = -16 + 300

h(1) = 284ft

Hence the height of the object after 1 sec is 284 feet

Learn more on maximum height here: brainly.com/question/12446886

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