Question

The area of a rectangle is given by the trinomial y^ 2 +4y-45. If the length of the rectangle is y + 9 , what is the width of the rectangle?

Answer 1

Step-by-step explanation:

Area of rectangle =L×W

Width =Area

$w idth= \frac{area \ }{length} \\ \\width = \frac{ {y}^{2} + 4y - 45}{y + 9} \\ \\ = \frac{(y - 5)(y + 9)}{(y + 9)} \\ \\ width = y - 5$