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3 years ago

Three fifths of a whole

Mathematics

1 answer:

nataly862011 [7]3 years ago

6 0

3/5 you split something into 5 pieces than shade in 3 <span />

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A) work out the radius of the mercury, giving your answer as an ordinary number

guapka [62]

Answer:

a. 2,440 km

b. $1.33*10^{27} kg$

Step-by-step explanation:

a. Diameter of Mercury = $4.88*10^3$

Radius of Mercury = ½ of its diameter = $\frac{4.88*10^3}{2}$

Radius of Mercury = $2.44*10^3$

To convert the radius to ordinary number, multiply 2.44 by 1,000.

Radius of Mercury as an ordinary number = $2.44*1,000 = 2,440 km$

b. Mass of Jupiter = $1.898*10^{27} kg$

Mass of Saturn = $5.68*10^{26} kg$

Difference between mass of Jupiter and mass of Saturn = $1.898*10^{27} - 5.68*10^{26}$ (subtract 5.68 from 1.898 = 5.68. we would retain the largest exponent, which is raised to the lower of 27.)

$= 1.33*10^{27}$

7 0

3 years ago

On a coordinate plane, a straight line and a parallelogram are shown. The straight line has a negative slope and has a formula o

monitta

Answer:

(1,3)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Can someone answer this question please answer it correctly if it’s correct I will mark you brainliest

mash [69]

Answer:

Harry stains his shirt

1/5= 20%

15%

7 0

3 years ago

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What is the slope of the line through the points (–2, –1) and (8, –3)?

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Find the slope, denoted m

This is done by using the formula m = (y2 - y1)/(x2 - x1)

The slope for this problem is

m = [-3 - (-1)]/[8 - (-2)]

m = -2/10 = -1/5

7 0

2 years ago

Given: m∠EYL=72°<br> Find: mEHL , mLVE

White raven [17]

Answer:

Part 1) The measure of arc EHL is $108\°$

Part 2) The measure of angle LVE is $54\°$

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$m$

we have

$m$

substitute

$72\°=\frac{1}{2}(y-x)$

$144\°=(y-x)$

$y=144\°+x$ ------> equation A

Remember that

$x+y=360\°$ -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

$x+(144\°+x)=360\°$

$2x=360\°-144\°$

$x=216\°/2=108\°$

Find the value of y

$y=144\°+x$

$y=144\°+108\°=252\°$

therefore

The measure of arc EHL is $108\°$

The measure of arc EVL is $252\°$

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

$m$

we have

$x=108\°$

substitute

$m$

3 0

3 years ago