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Answer:
The equation of ellipse centered at the origin
Step-by-step explanation:
given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)
The foci are (-C,0) and (C ,0)
Given data (±√8,0)
the focus has x-coordinates so the focus is lie on x- axis.
The major axis also lie on x-axis
The minor axis lies on y-axis so c0-vertices are (0,±√10)
given focus C = ae = √8
Given co-vertices ( minor axis) (0,±b) = (0,±√10)
b= √10
The relation between the focus and semi major axes and semi minor axes are
The equation of ellipse formula
we know that
<u>Final answer:</u>-
<u>The equation of ellipse centered at the origin</u>
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For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.