Question

A bowl of candy is sitting on the counter. If there are twelve blue pieces, fourteen red pieces, and six yellow pieces in the bowl, what is the probability of randomly selecting a blue piece?

Answer 1

Answer:

$\frac{3}{8}$  or 37.5%

Step-by-step explanation:

A bowl of candy is sitting on the counter.

Blue pieces = 12

Red pieces = 14

Yellow pieces = 6

Total candy = 12 + 14 + 6 = 32 pieces

The probability of randomly selecting a blue piece = $\frac{12}{32}$ =  $\frac{3}{8}$

The probability of randomly selecting a blue piece = $\frac{3}{8}$ 37.5%

Answer 2

If you add 12(blue) 14(red) 6(yellow) you get 32 so 12/32 is 0.37