Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law
which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then
<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:
Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:
If B is intersection of two disjoint sets then
Then (1) becomes
<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then
<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.
From axiom P(E)≥0
Therefore,
P(A)≥P(B)
-13F is less than -12F and -9F is greater than -12F
Answer:
(B) and (C) are correct! :)
Step-by-step explanation:
Please mark as BRAINLIEST
Hope this helps tho!
Have a great day :))))
Answer: 0
Step-by-step explanation:
Given that :
Mean score on test = 5
Standard deviation on test = 2
Distribution = normal
The mean value when Converted to a z - distribution :
Zscore = (x - mean) / standard deviation.
Hence z score for the mean score will be :
X = mean score
Zscore = ( 5 - 5) / 2
Zscore = 0 / 2
Zscore = 0
Mean value when Converted to a z distribution will be 0
Answer:
I will put this into fractions for you- I hope you meant that
Step-by-step explanation:
15x turns into 30/2x
-4y turns into -8/2x
And finally 18 turns into 36/2
So the whole equation looks like this-
30/2x-8/2x=36/2
P.S. I just multiplied everything by 2 and put 2 as the denominator