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Harlamova29_29 [7]
3 years ago
11

What happens if you double 15?

Mathematics
2 answers:
Andrej [43]3 years ago
8 0

Answer:

It becomes 30

Step-by-step explanation:

When you double a number, it’s increases to two of itself .

So double of 15 means 15 x 2

= 30

katen-ka-za [31]3 years ago
6 0
It turn into 30 because 15+15 is 30 and 15•15 is 30 :)
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Please someone answer this, “what is the area of triangle ABC?”
prisoha [69]

Here's the solution,

The given triangle is an <u>equilateral triangle</u>, because it's all angles measure 60° each

now,

Area of an equilateral triangle :

=》

\dfrac{ \sqrt{3} }{4}  {a}^{2}

where,

  • a = 8 ( side measure )

=》

\dfrac{ \sqrt{3} }{4}  \times 8 \times 8

=》

\sqrt{3}  \times 16

=》

16 \sqrt{3} \:  \:  \:  cm {}^{2}

or

=》

27.71 \:  \: cm {}^{2}

4 0
3 years ago
Here is a list of numbers: <br> 19, 4, -13, -17, -2, -14, 20, 8, 6 <br> State the median.
denis-greek [22]

Answer:

4 is the median to your problem

8 0
3 years ago
Which value of p makes the equation 18+ 2 (3p – 8) = –37 true?
Volgvan

Answer:

p = -6.5

Step-by-step explanation:

<u>Given:</u>

  • 18+ 2 (3p – 8) = –37

<u>Solving for p:</u>

  • 18+ 2 (3p – 8) = –37
  • 18 + 6p - 16 = -37
  • 6p + 2 = -37
  • 6p = -37 - 2
  • 6p = -39
  • p = -39/6
  • p = -6.5

Option 2 is correct in the list

3 0
3 years ago
Plss help me and explaim too​
masya89 [10]

Answer:

a = b = 1

Step-by-step explanation:

The triangles are similar thus ratios of corresponding sides are equal, that is

\frac{10}{2} = \frac{5}{b} ( cross- multiply )

10b = 10 ( divide both sides by 10 )

b = 1

and

\frac{10}{2} = \frac{5}{a} ( cross- multiply )

10a = 10 ( divide both sides by 10 )

a = 1

Thus a = 1 and b = 1

3 0
3 years ago
Question is in the pictures.
Kipish [7]
<h3>Answer:</h3>

x/tan(x) is an even function

sec(x)/x is an odd function

<h3>Explanation:</h3>

<em>x/tan(x)</em>

For f(x) = x/tan(x), consider f(-x).

... f(-x) = -x/tan(-x)

Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...

... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)

The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.

_____

<em>sec(x)/x</em>

For g(x) = sec(x)/x, consider g(-x).

... g(-x) = sec(-x)/(-x)

Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...

... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)

The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.

6 0
3 years ago
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