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2 years ago

Attached a phot please help!

Mathematics

1 answer:

musickatia [10]2 years ago

6 0

Answer:

-5, -18
-5x -18x
(x -3)(6x -5)

Step-by-step explanation:

a) The factors of 90 are ...

90 = (-1)(-90) = (-2)(-45) = (-3)(-30) = (-5)(-18) = (-6)(-15) = (-9)(-10)

The sums of these factors are -91, -47, -33, -23, -21, -19.

The factor pair with the sum of -23 is of interest here. Those factors are ...

-5, -18

b) -23x = -5x -18x

c) The rewritten expression is ...

6x^2 -5x -18x +15

(6x^2 -5x) -(18x -15) . . . . group into pairs

x(6x -5) -3(6x -5) . . . . . . .factor each pair

(x -3)(6x -5) . . . . . . . . . . factor out the common factor (6x -5)

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2 years ago

Solve for n if s = 540 Enter the value in the box. 180(n − 2) = s

netineya [11]

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3 years ago

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How do you solve this type of problem?

Aleonysh [2.5K]

The price of ticket last year is $ 1231.65

Solution:

Given that,

This year, Sophia paid $1,071 for season tickets to her favorite baseball team , which is 15% cheaper than last year

To find: Price of season ticket last year

Let the price of season ticket last year be "x"

Therefore, according to question

Price of ticket this year is 15 % cheaper than price of ticket last year

1071 = price of ticket last year - 15 % of 1071

1071 = x - 15 % of 1071

Solve the above expression for "x"

$1071 = x - 15 \% \times 1071\\\\1071 = x - \frac{15}{100} \times 1071\\\\1071 = x - 0.15 \times 1071\\\\1071 = x - 160.65\\\\x = 1071 + 160.65\\\\x = 1231.65$

Thus price of ticket last year is $ 1231.65

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3 years ago

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3 years ago