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3 years ago

Plz help with this math problem

Mathematics

1 answer:

Virty [35]3 years ago

4 0

Re-upload the photo you posted because it isnt showing up :(

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Can someone help me please. Question: draw and label a picture of the following terms

frutty [35]

Answer:

Please see attached

Step-by-step explanation:

3 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

Decrease <br>133 in the ratio 7:2

love history [14]

Answer:

Step-by-step explanation

2/7× 133=38

6 0

2 years ago

What is 9 copies of 3.65

Nataly_w [17]

I believe that you are doing multiplication with this.

So… 9 x 3.65 = 32.85

Hope this helps. :)

3 0

3 years ago

WHO WANTS 20 POINTS!!!!!!!!!!!!!! What is the value of x? Enter your answer in the box. x = Rectangle with a hash mark on the to

adell [148]

X=6
6x5=30
30+10=40
Have a nice day!

5 0

3 years ago

Read 2 more answers