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3 years ago

If K is the midpoint of JL, JK = 9x -1 and KL = 2x +27, find JL

Mathematics

2 answers:

alina1380 [7]3 years ago

6 0

Answer:

<h2>JL is 70 units long.</h2>

Step-by-step explanation:

Givens

K is the midpoint of JL. Where JL = 11x + 26.

JK = KL by midpoint definition.
JK = 9x - 1 by given.
KL = 2x + 27 by given.

Replacing each expression, we have

JK = KL

9x - 1 = 2x + 27

9x - 2x = 27 + 1

7x = 28

x = 28/7

x = 4

Replacing this value in JL expression.

JL = 11x + 26

JL = 11(4) + 26

JL = 44 + 26

JL = 70 units.

Therefore, JL is 70 units long.

Liula [17]3 years ago

3 0

Answer:

JL = 70

Step-by-step explanation:

Since K is the midpoint of JL then JK = KL and

JL = JK + KL = 9x - 1 + 2x + 27 = 11x + 26

solve for x using JK = KL

9x - 1 = 2x + 27 ( subtract 2x from both sides )

7x - 1 = 27 ( add 1 to both sides )

7x = 28 ( divide both sides by 7 )

x = 4, hence

JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70

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