Question

If K is the midpoint of JL, JK = 9x -1 and KL = 2x +27, find JL

Answer 1

Answer:

JL is 70 units long.

Step-by-step explanation:

Givens

• K is the midpoint of JL. Where JL = 11x + 26.

• JK = KL by midpoint definition.
• JK = 9x - 1  by given.
• KL = 2x + 27 by given.

Replacing each expression, we have

JK = KL

9x - 1 = 2x + 27

9x - 2x = 27 + 1

7x = 28

x = 28/7

x = 4

Replacing this value in JL expression.

JL = 11x + 26

JL = 11(4) + 26

JL = 44 + 26

JL = 70 units.

Therefore, JL is 70 units long.

Answer 2

Answer:

JL = 70

Step-by-step explanation:

Since K is the midpoint of JL then JK = KL and

JL = JK + KL = 9x - 1 + 2x + 27 = 11x + 26

solve for x using JK = KL

9x - 1 = 2x + 27 ( subtract 2x from both sides )

7x - 1 = 27 ( add 1 to both sides )

7x = 28 ( divide both sides by 7 )

x = 4, hence

JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70