Answer:
Step-by-step explanation:
Let, 
Now, us simplify the given differential equation and write it in terms of D,
or, 
or, 
We have our auxiliary equation:
or, 
or, 
Therefore our solution is,
and, 
Applying the boundary conditions, we get,
Solving them gives us,
Hence,
First you have to factor (aka, multiply) your binomial (which is what you have written) usually it helps to organize your thinking, and help tell what you need to multiply, to use the binomial chicken(or crab claw, what ever you want to call it) which basically you draw two arches, one arch connecting the 3 and 4, and then the other the 3 and 9i. on the opposite side (depending on wheater you connected then from the top or bottom) you connect (with an arch) the 6i and the four, and then the 6i to the 9i.
so now you multiply each piece you've connected:
3 x 4= 12
3 x 9i= 27i
6i x 4= 24i
6i x 9i= 54i^2
after you've done this you can move on to putting it into standard form, which just means you put things in descending order, depending on how many exponents the x (or in this case i) has.
your largest exponent is 54i^2, so that's first in out equation, next 27i, and 24i (you can combine these because they are like term) which equals 51i, after that you just add the 12 on the end, so the final equation looks like this:
54i^2+51i+12
I think the answer would be x= 4/7 y = +-16/7
Answer:
1.35
Step-by-step explanation:
13.5/100 times 10 = 1.35
Answer: 
This is the same as writing y < (-1/2)x+3
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Explanation:
The dashed boundary line goes through (0,3) and (4,1)
Apply the slope formula for those two points
m = (y2-y1)/(x2-x1)
m = (1-3)/(4-0)
m = -2/4
m = -1/2
The slope of the dashed line is -1/2. The y intercept is 3. So we go from y = mx+b to y = (-1/2)x+3 to represent the equation of the dashed line. This is the same as writing 
We shade below the dashed line to represent the inequality . Points in the shaded region are solutions to the inequality. One example point is (0,0).
Note that we don't have "or equal to" as part of the inequality sign because we are not including points on the boundary. A solid line, rather than a dashed line, would include points on the boundary.
